Projecteuler.net – Problem 1 – Java solution

http://projecteuler.net/problem=1

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.Find the sum of all the multiples of 3 or 5 below 1000.

My one function solution.

private static int euler001() {
    int sum = 0;
    for (int i=1; i < 1000; i++) {
        if (i%3 == 0 || i%5 == 0) {
            sum += i;
        }
    }
    return sum;
}
This entry was posted in Java, Project Euler. Bookmark the permalink.

Leave a Reply