Projecteuler.net – Problem 1 – C solution

http://projecteuler.net/problem=1

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.


Here is my solution.

– Josh

This entry was posted in C, Project Euler. Bookmark the permalink.

Leave a Reply